A particle is projected with an angle of projection $θ$ to the horizontal line passing through the points (P, Q) and (Q, P) referred to horizontal and vertical axes (can be treated as X-axis and Y-axis, respectively).
The angle of projection can be given by [AIIMS 2015]

Question

A particle is projected with an angle of projection

θ

to the horizontal line passing through the points (P, Q) and (Q, P) referred to horizontal and vertical axes (can be treated as X-axis and Y-axis, respectively).
The angle of projection can be given by [AIIMS 2015]

Infinity Learn · Accepted Answer

The equation of trajectory,$$y=xtan$$α$$1-xRQ=Ptan$$θ$$1-PRand$$  $$P=Qtan$$θ$$1-QROn$$ dividing Eq. (i) by Eq. (ii), we $$getQ2P2=$$[$$1-P/R$$][$$1-Q/R$$]$$1RP3-Q3=P2-Q2$$⇒  $$R=P3-Q3P2-Q2=P2+PQ+Q2P+QNow$$,  $$QP=$$$$tan$$θ$$1-P(P+Q)P2+PQ+Q2=$$$$tan$$θ$$P2+PQ+Q2-P2-PQP2+PQ+Q2$$⇒  $$tan$$θ$$=P2+Q2+PQPQ$$⇒  θ$$=$$$$tan$$$$-1P2+PQ+Q2PQ$$

A particle is projected with an angle of projection $θ$ to the horizontal line passing through the points (P, Q) and (Q, P) referred to horizontal and vertical axes (can be treated as X-axis and Y-axis, respectively).
The angle of projection can be given by [AIIMS 2015]

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A particle is projected with an angle of projection θ to the horizontal line passing through the points (P, Q) and (Q, P) referred to horizontal and vertical axes (can be treated as X-axis and Y-axis, respectively).The angle of projection can be given by [AIIMS 2015]

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

A particle is projected with an angle of projection $θ$ to the horizontal line passing through the points (P, Q) and (Q, P) referred to horizontal and vertical axes (can be treated as X-axis and Y-axis, respectively).
The angle of projection can be given by [AIIMS 2015]