A particle is projected with a certain velocity at an angle α above the horizontal from the foot of an inclined plane of inclination $$30$$°. If the particle strikes the plane normally, thenα is equal to

Question

A particle is projected with a certain velocity at an angle α above the horizontal from the foot of an inclined plane of inclination $$30$$°. If the particle strikes the plane normally, thenα is equal to

Infinity Learn · Accepted Answer

$$tAB=$$ time of flight of projectile $$=2usin$$α$$-30$$°$$gcos30$$° Now component of velocity along the plane becomes zero at point B.  $$0=ucos$$α$$-30$$°$$-gsin30$$°×T ucosα$$-30$$°$$=gsin30$$°×$$2usin$$α$$-30$$°$$gcos30$$° $$tan$$α$$-30$$°$$=cot30$$°$$2=32$$ α$$=30$$°$$+$$$$tan$$$$-132$$

A particle is projected with a certain velocity at an angle $α$ above the horizontal from the foot of an inclined plane of inclination 30°. If the particle strikes the plane normally, then $α$ is equal to

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A particle is projected with a certain velocity at an angle α above the horizontal from the foot of an inclined plane of inclination 30°. If the particle strikes the plane normally, thenα is equal to

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A particle is projected with a certain velocity at an angle $α$ above the horizontal from the foot of an inclined plane of inclination 30°. If the particle strikes the plane normally, then $α$ is equal to