A particle is projected with a certain velocity at an angle α above the horizontal from the foot of an inclined plane of inclination 30o. If the particle strikes the plane normally,then a is equal to

tAB= time of flight of projectile =2usin⁡α−30∘gcos⁡30∘Now component of velocity along theplane becomes zero at Point B.0=ucos⁡α−30∘−gsin⁡30∘×Tor ucos⁡α−30∘=gsin⁡30∘×2usin⁡α−30∘gcos⁡30∘or  tan⁡α−30∘=cot⁡30∘2=32or  α=30∘+tan−1⁡32