A particle is projected with speed 25 m/s at angle 53o from horizontal in front of an inclined plane mirror as shown in figure. Choose the correct option(s) (g = 10 m/s2).

Relative speed will be minimum (zero) when velocity of object will be parallel to plane mirror. tan⁡α=usin⁡θ−gtucos⁡θ⇒34=25⋅45−10t25⋅35⇒ 34=20−10t15⇒45=80−40t⇒ 40t=35⇒t=78sAt maximum relative speed, the object moves normal to mirror. And it occurs when the particle hits the ground. Hence, maximum relative speed = 50 m/s