Questions
A particle is projected with a speed v0 at an angle above the horizontal surface such that the ratio of the kinetic energy at the highest point and the point of projection is 3:4. The change in velocity of the particle between these two points is
detailed solution
Correct option is A
The ratio of the kinetic energy at the highest point and point of projection isKHK0=34⇒(1/2)mv0cosθ2(1/2)mv02=34⇒cos2θ=34⇒θ=π6Change in velocity =v0sinθ=v0/2.Talk to our academic expert!
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A ball is projected obliquely with a velocity 49 ms–1 strikes the ground at a distance of 245 m from the point of projection. It remained in air for
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