A particle (1) is projected with speed V from a point O making an angle of $$30o$$ with the vertical. At the same instant, a second particle (2) is thrown vertically upwards with velocity v from a point A. The two particles reach H, the highest point on the parabolic path of particle (1) simultaneously. The ratio of $$V/v$$ is

Question

Infinity Learn · Accepted Answer

Time taken by particle $$1$$ to reach H is given $$byt=Vsin$$⁡$$60$$∘$$g=3V2gTime$$ taken by particle $$2$$ reach H is given byt′$$=vgNow$$    $$3V2g=vg$$  or  $$Vv=23$$

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