A particle is projected with a speed v at 450 with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height h , is:
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a
mvh22
b
mv2h2
c
mvh32
d
mvh2
answer is D.
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Detailed Solution
Velocity of a particle at maximum height h is v'=vcosθ Where v= initial velocity of the particle at which it is projected,θ= angle of projectionAngular momentum, L=mv'h=mv cosθh =mvhcos450=mvh2
A particle is projected with a speed v at 450 with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height h , is: