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A particle is projected with a speed $v$ at $45^{0}$ with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height $h$ , is:

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Correct option is D

Velocity of a particle at maximum height h is v'=vcosθ Where v= initial velocity of the particle at which it is projected,θ= angle of projectionAngular momentum, L=mv'h=mv cosθh =mvhcos450=mvh2

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A particle is projected with a speed v at 450 with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height h , is:

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A particle is projected with a speed $v$ at $45^{0}$ with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height $h$ , is: