Questions
A particle is projected with a velocity 40 m/s at an angle with the horizontal. Find the change in velocity when it is at a height of 15 m from the ground, (g = 10 )
detailed solution
Correct option is A
Horizontal velocity remains constantVertical velocity changesInitial vertical velocity usinθ=40sin300 = 20 m/sAt height 15 m its vertical velocity uy2 = 202−2g15= 400 – 300 uy2 = 202−2g15Change in velocity = 20 – 10 = 10 m/s.Similar Questions
Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.
Reason : Range of projectile does not depend on the initial velocity of a body.
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