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A particle is projected with a velocity 40 m/s at an angle 30o with the horizontal. Find the change in velocity when it is at a height of 15 m from the ground, (g = 10 m/s2)

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a
10 m/s
b
20 m/s
c
5 m/s
d
203  m/s

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detailed solution

Correct option is A

Horizontal velocity remains constantVertical velocity changesInitial vertical velocity  usinθ=40sin300                                              = 20 m/sAt height 15 m its vertical velocity uy2 = 202−2g15= 400 – 300 uy2 = 202−2g15Change in velocity = 20 – 10 = 10 m/s.

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Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.

Reason : Range of projectile does not depend on the initial velocity of a body.


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