A particle is projected with a velocity $$40$$ $$m/s$$ at an angle $$30o$$ with the horizontal. Find the change in velocity when it is at a height of $$15$$ m from the ground, (g$$ $$=$$ $$10$$ $$m/s2)

Question

A particle is projected with a velocity $$40$$ $$m/s$$ at an angle $$30o$$ with the horizontal. Find the change in velocity when it is at a height of $$15$$ m from the ground, (g$$ $$=$$ $$10$$ $$m/s2)

Infinity Learn · Accepted Answer

Horizontal velocity remains constantVertical velocity changesInitial vertical velocity  usinθ$$=40sin300$$                                              $$=$$ $$20$$ $$m/sAt$$ height $$15$$ m its vertical velocity $$uy2$$ $$=$$ $$202$$−$$2g15=$$ $$400$$ – $$300$$ $$uy2$$ $$=$$ $$202$$−$$2g15Change$$ in velocity $$=$$ $$20$$ – $$10$$ $$=$$ $$10$$ $$m/s$$.

A particle is projected with a velocity 40 m/s at an angle $30^{o}$ with the horizontal. Find the change in velocity when it is at a height of 15 m from the ground, (g = 10 $m / s^{2}$ )

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A particle is projected with a velocity 40 m/s at an angle 30o with the horizontal. Find the change in velocity when it is at a height of 15 m from the ground, (g = 10 m/s2)

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A particle is projected with a velocity 40 m/s at an angle $30^{o}$ with the horizontal. Find the change in velocity when it is at a height of 15 m from the ground, (g = 10 $m / s^{2}$ )