First slide
Projection Under uniform Acceleration

A particle is projected with a velocity 40 m/s at an angle 30o with the horizontal. Find the change in velocity when it is at a height of 15 m from the ground, (g = 10 m/s2)


Horizontal velocity remains constant
Vertical velocity changes
Initial vertical velocity  usinθ=40sin300
                                              = 20 m/s
At height 15 m its vertical velocity
= 400 – 300
Change in velocity = 20 – 10 = 10 m/s.

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