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Q.

A particle is projected with a velocity of 30 ms-1, at an angle of θ0 = tan-134. After 1 s, the particle is moving at an angle θ to the horizontal, where tanθ will be equal to (Take, g = 10 ms-2 )

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a

1

b

2

c

12

d

13

answer is D.

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Detailed Solution

ux=ucosθ0=30×45=24 ms-1 and uy=usinθ0=30×35=18 ms-1After 1 s, ux will remain same and uy will decrease by 10 ms-1 or it will become 8 ms-1.∴  tanθ = vyvx = 824 = 13
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