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A particle is projected with a velocity of 10ms-1  at an angle 37° with horizontal. A bird moves along the path of projected particle with constant speed of 4 ms-1. Find the acceleration of bird when it is at highest point of path of particle.(g = 10ms-2

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By Expert Faculty of Sri Chaitanya
a
zero
b
10 ms-2
c
5 ms-2
d
2.5 ms-2
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detailed solution

Correct option is D

For Particle Mg=Mucosθ2R⇒R=u2cos2θgFor  Bird,  an=v2R=v2u2cos2θ×g=42102cos2370×10= 2.5 ms-2


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