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Question

A particle is projected with a velocity of 10ms-1  at an angle 37° with horizontal. A bird moves along the path of projected particle with constant speed of 4 ms-1. Find the acceleration of bird when it is at highest point of path of particle.(g = 10ms-2

Easy
Solution

ForParticleMg=Mucosθ2R
R=u2cos2θg
ForBird,an=v2R=v2u2cos2θ×g
=42102cos2370×10= 2.5 ms-2

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