A particle is projected with a velocity of 10ms-1 at an angle 37° with horizontal. A bird moves along the path of projected particle with constant speed of 4 ms-1. Find the acceleration of bird when it is at highest point of path of particle.(g = 10ms-2)

see full answer

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

zero

10 ms-2

5 ms-2

2.5 ms-2

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

For Particle Mg=Mucosθ2R⇒R=u2cos2θgFor Bird, an=v2R=v2u2cos2θ×g=42102cos2370×10= 2.5 ms-2

Watch 3-min video & get full concept clarity