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A particle is projected with a velocity of 10 ${ms}^{- 1}$ at an angle $37 °$ with horizontal. A bird moves along the path of projected particle with constant speed of 4 ${ms}^{- 1}$ . Find the acceleration of bird when it is at highest point of path of particle.(g = 10 ${ms}^{- 2}$ )

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zero

10 ms-2

5 ms-2

2.5 ms-2

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detailed solution

Correct option is D

For Particle Mg=Mucosθ2R⇒R=u2cos2θgFor Bird, an=v2R=v2u2cos2θ×g=42102cos2370×10= 2.5 ms-2

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A particle is projected with a velocity of 10ms-1 at an angle 37° with horizontal. A bird moves along the path of projected particle with constant speed of 4 ms-1. Find the acceleration of bird when it is at highest point of path of particle.(g = 10ms-2)

Unlock the full solution & master the concept.

Ready to Test Your Skills?

free study material

A particle is projected with a velocity of 10 ${ms}^{- 1}$ at an angle $37 °$ with horizontal. A bird moves along the path of projected particle with constant speed of 4 ${ms}^{- 1}$ . Find the acceleration of bird when it is at highest point of path of particle.(g = 10 ${ms}^{- 2}$ )