Questions
A particle is projected with a velocity 40 m/s at an angle 300 with the horizontal. The magnitude of change in velocity when it is at a height of 15 m from the ground is
detailed solution
Correct option is A
There is no change in horizontal velocityVertical velocity at a height h vy2=(usinθ)2−2gyvy2=40122−2(10)15vy2=100vy=10m/sChange in velocityusinθ−1040(0.5)−1020−10=10m/sTalk to our academic expert!
Similar Questions
Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.
Reason : Range of projectile does not depend on the initial velocity of a body.
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