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Q.

A particle is projected with velocity 10m/s making an angle α with horizontal, when the particle is at the highest position of its trajectory, its angular momentum about the point of projection is ‘L’. If the particle is projected with velocity 20m/s at an angle α with horizontal, its angular momentum about the point of projection is

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a

24 L

b

16 L

c

8 L

d

4 L

answer is C.

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Detailed Solution

L=mu3 cosα.sin2α2g⇒L∝u3∴L'L=20103⇒L'=8L
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A particle is projected with velocity 10m/s making an angle α with horizontal, when the particle is at the highest position of its trajectory, its angular momentum about the point of projection is ‘L’. If the particle is projected with velocity 20m/s at an angle α with horizontal, its angular momentum about the point of projection is