A particle is projected with a velocity ν, so that its range on a horizontal plane is twice the greatest height attained. If g is acceleration due to gravity, then its range is
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a
4v25g
b
4g5v2
c
4v35g2
d
4v5g2
answer is A.
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Detailed Solution
H=v2sin2θ2g and R=v2sin2θgSince, R=2H, so v2sin2θg=2v2sin2θ2gor 2sinθcosθ=sin2θ or tanθ=2∴R=v22gsinθcosθ=2v2g2515=4v25g
A particle is projected with a velocity ν, so that its range on a horizontal plane is twice the greatest height attained. If g is acceleration due to gravity, then its range is