Questions
A particle is projected with a velocity , so that its range on a horizontal plane is twice the greatest height attained. If g is acceleration due to gravity, then its range is
detailed solution
Correct option is A
H=v2sin2θ2g and R=v2sin2θgSince, R=2H, so v2sin2θg=2v2sin2θ2gor 2sinθcosθ=sin2θ or tanθ=2∴R=v22gsinθcosθ=2v2g2515=4v25gTalk to our academic expert!
Similar Questions
Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.
Reason : Range of projectile does not depend on the initial velocity of a body.
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