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A particle is projected with velocity $\vec{u} = (4 \hat{i} + 3 \hat{j}) m / s$ then the radius of curvature of its trajectory at the highest position is (Take g = 10 m/s²)

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Correct option is A

At the highest position radius of curvature is given by g=ucosα2ρ⇒ρ=ucosα2g=4210m=1.6 m

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A particle is projected with velocity u→=4i^+3j^m/s then the radius of curvature of its trajectory at the highest position is (Take g = 10 m/s2)

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A particle is projected with velocity $\vec{u} = (4 \hat{i} + 3 \hat{j}) m / s$ then the radius of curvature of its trajectory at the highest position is (Take g = 10 m/s²)