A particle is projected with a velocity u making an angle θ with the horizontal. At any instant, its velocity V is at right angles to its initial velocity u ; then V is
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a
ucosθ
b
utanθ
c
ucotθ
d
u secθ
answer is C.
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Detailed Solution
Because horizontal component of velocity remains constant in projectile motion, henceucosθ=Vcos90∘−θucosθ=Vsinθ or V=ucotθ