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A particle is projected with a velocity u making an angle θ with the horizontal. At any instant, its velocity V is at right angles to its initial velocity u ; then V is

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a
ucos⁡θ
b
utan⁡θ
c
ucot⁡θ
d
u sec⁡θ

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detailed solution

Correct option is C

Because horizontal component of velocity remains constant in projectile motion, henceucos⁡θ=Vcos⁡90∘−θucos⁡θ=Vsin⁡θ or V=ucot⁡θ


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Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.

Reason : Range of projectile does not depend on the initial velocity of a body.


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