Questions
A particle is projected with a velocity u. So that its horizontal range and maximum height reached are equal. The maximum height reached is
detailed solution
Correct option is D
R=Hmax2u2sinθcosθg=u2sin2θ2gtanθ=4sinθ=417Hmax=u2.16/172g=8u217gTalk to our academic expert!
Similar Questions
Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.
Reason : Range of projectile does not depend on the initial velocity of a body.
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