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A particle is projected with a velocity u.  So that its horizontal range and maximum height reached are equal.  The maximum height reached is

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a
2u2/3g
b
4u2/5g
c
u2/g
d
8u2/17g

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detailed solution

Correct option is D

R=Hmax2u2sinθcosθg=u2sin2θ2gtanθ=4sinθ=417Hmax=u2.16/172g=8u217g

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Similar Questions

Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.

Reason : Range of projectile does not depend on the initial velocity of a body.


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