A particle is projected in XY-plane with a velocity u=(2i^+3j^)ms−1 at t = 0 from origin. Its acceleration is a=i^+4j^. Then,

(1) Here, acceleration is constant but not directed in the direction of initial velocity.So, path is parabolic.(3) r=ut+12at2or r=2i^+3j^×1+12i^+4j^×12=2.5i^+5j^m(4) ∵v=u+at=2i^+3j^+i^+4j^=3i^+7j^∴Speed=v=58ms−1