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An α-particle and a proton are projected in a uniform magnetic field in a direction perpendicular to the field. If r be the radius of circular path energy of α-particle to that of proton is
detailed solution
Correct option is C
kinetic energy, K=12mv2⇒v=2Km∴r=vω=2K/mQB/m=2KmQB⇒K=Q2B2r22m⇒K∝Q2r2m ∴KαKp=QαQp2.rαrp2.mpmα2=2ee2.22.m4m=4Talk to our academic expert!
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A charged beam consisting of electrons and positrons enter into a region of uniform magnetic field B perpendicular to field, with a speed v. The maximum separation between an electron and a positron will be (mass of electron = mass of positron = m)
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