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A particle is at rest at the origin. Mass of the particle is 2 kg. It is displaced by 4m along the x-axis under the influence of a force F→=(2x)i^ N, then find velocity of the particle is

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Detailed Solution

W=∫04F→.dx→=∫04(2xi^).(dxi^)=2x2204J⇒W=16 JBy work energy theorem, 12×2×V2−0=16⇒V=4 m/s
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