A particle in SHM is described by the displacement equation x(t)=Acos(ωt+θ). If the initial (t = 0) position of the particle is 1 cm and its initial velocity is π cm/s, what is its amplitude? The angular frequency of the particle is πs-1

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1 cm

2 cm

2.5 cm

answer is B.

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Detailed Solution

Given, v=π cm/sec, x=1 cm and ω=πs−1using v=ωa2−x2 ⇒π=πa2−1⇒1=a2-1 ⇒a=2cm

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