A particle in SHM is described by the displacement function x(t)=Acos⁡(ωt+ϕ). If the initial (t = 0) position of the particle is 1 cm, its initial velocity is p cms-1 and its angular frequency is π rad s-1 , then the amplitude of its motion is

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π cm

2 cm

√2 cm

1 cm

answer is C.

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Detailed Solution

v=ωa2−y2

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