Download the app

Questions  

A particle in S.H.M. is described by the displacement function x(t) = a cos (ωt + θ).If the initial (t = 0) position of the particle is I cm and its initial velocity is π cm/s. The angular frequency of the particle is π rad/s, then its amplitude is

a
1 cm
b
2  cm
c
2 cm
d
2.5 cm

detailed solution

Correct option is B

x = a cos (ωt + θ)------------(i)And v = dxdt = -aω sin(ωt+θ)--------(ii)Given at t = 0, x = 1 cm and v = π and ω = πPutting these values in equation (i) and (ii), we will getsin θ = -1a and cos θ = 1A⇒ sin2θ + cos2θ = (-1a)2+(1a)2  ⇒ a = 2 cm

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

The identical springs of constant ‘K’ are connected in series and parallel as shown in figure A mass M is suspended from them. The ratio of their frequencies of vertical oscillations will be


phone icon
whats app icon