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For a particle in S.H.M., if the amplitude of displacement is 'a' and the amplitude of velocity is 'v' the amplitude of acceleration is
detailed solution
Correct option is B
Maximum velocity v = ωa ⇒ω=vaMaximum acceleration amax = ω2a =v2a2 a= v2aTalk to our academic expert!
Similar Questions
The identical springs of constant ‘K’ are connected in series and parallel as shown in figure A mass M is suspended from them. The ratio of their frequencies of vertical oscillations will be
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