A particle of specific charge q/m=π C/kg is projected from the origin towards positive x-axis with a velocity of 10 m/s in a uniform magnetic field B→=−2k^ Tesla. The velocity V→ of the particle after time t = 1/6 s will be

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

(5i^+53j^) m/s

10j^ m/s

(53i^−5j^) m/s

−10j^ m/s

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Time period T=2πmqB=1 sThus, the particle will be at P after t=16 s∴ V→=10(cos⁡60i^+sin⁡60j^) =5(i^+3j^) m/s

Watch 3-min video & get full concept clarity