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Questions  

A particle of specific charge q/m=π C/kg is projected from the origin towards positive x-axis with a velocity of 10 m/s in a uniform magnetic field B=2k^  Tesla. The velocity V of the particle after time t = 1/6 s will be

a
(5i^+53j^) m/s
b
10j^ m/s
c
(53i^−5j^) m/s
d
−10j^ m/s

detailed solution

Correct option is A

Time period T=2πmqB=1 sThus, the particle will be at P after t=16 s∴ V→=10(cos⁡60i^+sin⁡60j^)       =5(i^+3j^) m/s

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