A particle of specific charge q/m=π C/kg is projected from the origin towards positive x-axis with a velocity of 10 m/s in a uniform magnetic field B→=−2k^ Tesla. The velocity V→ of the particle after time t = 1/6 s will be
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a
(5i^+53j^) m/s
b
10j^ m/s
c
(53i^−5j^) m/s
d
−10j^ m/s
answer is A.
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Detailed Solution
Time period T=2πmqB=1 sThus, the particle will be at P after t=16 s∴ V→=10(cos60i^+sin60j^) =5(i^+3j^) m/s