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A particle of specific charge qm=π C/kg is projected from the origin towards positive x-axis with a velocity of 10 m/s in a uniform magnetic field B→=−2k^T. The velocity v of particle after time t=112s will be (in m/s)

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a

5i^+3 j^

b

53i^+ j^

c

53i^- j^

d

5i^+ j^

answer is B.

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Detailed Solution

The particle will move in xy plane in circular path with angular velocity ω=αB=2π rad/s. Therefore angle of rotation =2π×112rad=300 v→=10 cos 30i^ + sin 30 j^v→=10 32 i^+12 j^ = 5 3i^ + j^ m/s

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A particle of specific charge qm=π C/kg is projected from the origin towards positive x-axis with a velocity of 10 m/s in a uniform magnetic field B→=−2k^T. The velocity v of particle after time t=112s will be (in m/s)