First slide
Force on a charged particle moving in a magnetic field
Question

A particle of specific charge qm=π    C/kg is projected from the origin towards positive x-axis with a velocity of 10 m/s in a uniform magnetic field B=2k^T. The velocity v of particle after time t=112s  will be (in m/s)

Moderate
Solution

The particle will move in xy plane in circular path with angular velocity 

ω=αB=2π rad/s. Therefore angle of rotation =2π×112rad=300 

v=10cos30i^+  sin  30j^v=1032  i^+12j^=  5  3i^  +  j^  m/s

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