A particle starting from rest moves with constant acceleration. If it takes 5 sec to reach the speed 18 km/h. finda) The average velocity during this periodb) The distance travelled by the particle during this period

given initial velocity=u=0 final velocity=v=18 km/h=18×518=5m/s time t=5 sec acceleration=a=v−ut=5−05=1m/s2 s=ut+12at2⇒s=12.5m  a) Average velocity Vavg=total displacementtime taken=12.55=2.5m/s    b) Distance travelled is 12.5m