Questions
A particle starting from rest moves with constant acceleration. If it takes 5 sec to reach the speed 18 km/h. find
a) The average velocity during this period
b) The distance travelled by the particle during this period
detailed solution
Correct option is A
given initial velocity=u=0 final velocity=v=18 km/h=18×518=5m/s time t=5 sec acceleration=a=v−ut=5−05=1m/s2 s=ut+12at2⇒s=12.5m a) Average velocity Vavg=total displacementtime taken=12.55=2.5m/s b) Distance travelled is 12.5m
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