A particle starting from rest and moving with a uniform acceleration along a straight line covers distances a and b in first p and next q second. The acceleration of the particle is
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a
a+b2(p+q)
b
2b(q+2p)q
c
2ap(p+2p)
d
a+b(p+q)2
answer is B.
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Detailed Solution
Let x be the acceleration. Then,$$a=12xp2a+b=+12x(p+q)2Solving these two equations, we getx=2b(q+2p)q