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Q.

A particle starting from rest and moving with a uniform acceleration along a straight line covers distances a and b in first p and next q second. The acceleration of the particle is

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a

a+b2(p+q)

b

2b(q+2p)q

c

2ap(p+2p)

d

a+b(p+q)2

answer is B.

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Detailed Solution

Let x be the acceleration. Then,$$a=12xp2a+b=+12x(p+q)2Solving these two equations, we getx=2b(q+2p)q
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