A particle starts from the origin at t=0 with an initial velocity of 3.0i^ m/s and moves in the x−y plane with a constant acceleration 6.0i^+4.0j^m/s2. The x-coordinate of the particle at the instant when its y–coordinate is 32m is ________ meters.
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
50
b
32
c
60
d
40
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Given : ux=3m/s,ax=6m/s2,ay=4m/s2By applying equations of Kinematics : y=uyt+12ayt2 ⇒32=0+12×4×t2⇒t2=16 ⇒t=4s Now, x=uxt+12axt2 ⇒x=3×4+12×6×16 ⇒x=12+48=60m