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Q.

A particle starts from the origin at t=0 with an initial velocity of 3.0i^ m/s and moves in the x−y plane with a constant acceleration 6.0i^+4.0j^m/s2. The  x-coordinate of the particle at the instant when its y–coordinate is 32m is ________ meters.

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a

50

b

32

c

60

d

40

answer is C.

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Detailed Solution

Given  : ux=3m/s,ax=6m/s2,ay=4m/s2​By applying equations of Kinematics  : ​ y=uyt+12ayt2    ​⇒32=0+12×4×t2⇒t2=16    ​⇒t=4s    ​Now, x=uxt+12axt2 ⇒x=3×4+12×6×16​       ⇒x=12+48=60m
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