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Q.

A particle starts from the origin with a velocity of 10 m s-1 and moves with a constant acceleration till the velocity increases to 50 ms-1. At that instant, the acceleration is suddenly reversed. What will be the velocity of the particle, when it returns to the starting point?

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a

Zero

b

10ms−1

c

50ms−1

d

70ms−1

answer is D.

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Detailed Solution

2ax=(50)2−(10)2 and 2(−a)(−x)=v2−(50)2 This gives v2−(50)2=(50)2−(10)2 i.e.  v=70ms−1
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