A particle starts from point A moves along a straight line path with an aceleration given by a $$=$$ p $$-$$ qx where p,q are constants and x is distance from point A. The particle stops at point B. The maximum velocity of the paticle is

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Infinity Learn · Accepted Answer

Acceleration a $$=$$ $$(p$$ $$-$$ $$qx)The$$ velocity is maximum when $$dv/dx$$ $$=$$ $$0Now$$,   velocity is zero when a $$=$$ p $$-$$ qx $$=$$ $$0$$ i.e. x $$=$$ $$p/qNow$$, v. dv $$=$$ $$(p$$ $$-$$ $$qx)dx$$⇒∫$$0xmv$$ dv $$=p$$∫$$0pq$$ dv $$-q$$∫$$0pqxdx$$    ⇒$$vm=pq$$

A particle starts from point A moves along a straight line path with an aceleration given by a = p - qx where p,q are constants and x is distance from point A. The particle stops at point B. The maximum velocity of the paticle is

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