A particle starts from rest from the origin and moves along the X-axis. Its position as a function of time is given by x=6t2−t3, here x is in meters and t is in seconds. The velocity of the particle at the equilibrium position is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
6 m/s
b
- 12 m/s
c
12 m/s
d
- 6 m/s
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
At the equilibrium position a = 0. v = 12t - 3t2 and a = 12 - 6t