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Q.

A particle starts from rest and moves along a circular path of radius 5m with a tangential acceleration of constant magnitude. If the length of path traversed by the particle in 2 second is 20 m, its angular acceleration is

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a

2.5 rad/sec2

b

0.75 rad/sec2

c

1.5 rad/sec2

d

2 rad/sec2

answer is D.

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Detailed Solution

If at be the tangential acceleration of the particle, than S=12at.t2⇒at=2st2∴ α=atr=2Srt2=2×205×22rad/s2=2rad/sec2

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