A particle starts from rest and moves with acceleration a which varies with time t as a=kt where k is a constant. The displacement s of the particle at time t is
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a
12kt2
b
12at2
c
16at2
d
16kt2
answer is C.
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Detailed Solution
Initial velocity, u=0Acceleration a=kt (Where k is constant)⇒dvdt=kt∵a=dvdt⇒∫0vdv=∫0tktdtIntegrating both sides, we get v=kt22∵v=dxdt⇒dxdt=kt22⇒∫0x dx=∫0t k2t2dtAgain integrating both sides, we get x=k6t3=16kt.t2∴x=16at2