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A particle starts  from rest is moving with  uniform acceleration travels a distance x  in first 2 seconds and a distance y  in next two seconds, then relation between x and y is

a
y=x
b
y=2x
c
y=3x
d
y=4x

detailed solution

Correct option is C

displacement in first 2 seconds is x→     x=s=ut+12at2⇒x=12a22⇒x=2a---(1) displacement in first two , next two seconds(2+2=4) together is x+y→  x+y=s=ut+12at2⇒x+y=12at2⇒x+y=12a42⇒x+y=8a---(2) solving equations (1) &(2) y=3x

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