A particle starts its motion from rest under the action of a constant force, if the distance covered in first 10 seconds is S1 and that covered in the first 20 seconds is S2, then:

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S2 = S1

S2 = 2S1

S2 = 3S1

S2 = 4S1

answer is D.

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Detailed Solution

S1=12a102 and S2=12(a)202⇒S2=4S1

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