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A particle starts its motion from rest under the action of a constant force.  If the distance covered in the first 10 sec is x and that covered in the first 20 sec is y then

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a
y   =  2x
b
y  = 3x
c
y  =  4x
d
y  = x

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detailed solution

Correct option is C

A to B :     x  =  12 a (10)2A to C :    y  =  12 a (10+10)2Dividing second equation with first equation               yx   =    4         ∴    y   =    4x


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