First slide

Rectilinear Motion

Question

A particle starts its motion from rest under the action of a constant force. If the distance covered in the first 10 sec is x and that covered in the first 20 sec is y then

Easy

A

y = 2x
B

y = 3x
C

y = 4x
D

y = x

Solution

A to B : $x = \frac{1}{2} a {(10)}^{2}$
A to C : $y = \frac{1}{2} a {(10 + 10)}^{2}$
Dividing second equation with first equation
$\frac{y}{x} = 4$
$∴ y = 4 x$

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