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A particle starts its SHM from mean position at t = 0. If its time period is T and amplitude A then the distance travelled by the particle in the time from t = 0 to $t = \frac{5 T}{4}$ is

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detailed solution

Correct option is D

y=Asinωt in each T/4 time interval particle covers distance A

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A particle starts its SHM from mean position at t = 0. If its time period is T and amplitude A then the distance travelled by the particle in the time from t = 0 to t=5T4 is

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A particle starts its SHM from mean position at t = 0. If its time period is T and amplitude A then the distance travelled by the particle in the time from t = 0 to $t = \frac{5 T}{4}$ is