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Q.

A particle starts moving along a circle of radius 40π m with a constant tangential acceleration. If the velocity of the particle is 120 m/s at the end of the second revolution after the motion has begun, the tangential acceleration is

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a

40 m/s2

b

35 m/s2

c

45 m/s2

d

50 m/s2

answer is C.

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Detailed Solution

vf2−ui2=2(Rα)4π(120)2=2aT 4π40πaT=120×1202×4×40=45 m/s2

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