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A particle starts moving from rest along a straight line with constant acceleration of 2 m/s2. After 4 second it starts moving with constant retardation of 4 m/s2 and finally stops. Then total distance covered by the particle is

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a

16 m

b

36 m

c

24 m

d

32 m

answer is C.

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Detailed Solution

Maximum velocity of the particle, V=0+2×4m/s=8 m/s.∴ x1=0×4+12×2×42m=16 m and 0=82−2×4×x2⇒x2=648m=8 m∴ Total distance covered, x=x1+x2=16+8m=24 m

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