Questions
A particle starts moving from rest from the origin with constant acceleration of and continues to move along X-axis. After sometime it starts moving with constant retardation of and finally stops at a point. If the total distance traversed by the particle is 12 m, its maximum velocity is
detailed solution
Correct option is C
(3)Vm2=0+2 × 1×x1 ⇒ x1=Vm22and 0= Vm2−2 ×2 ×x2 ⇒ x2=Vm24Now, x1 + x2 =12 ⇒ Vm22+Vm24=12 ⇒Vm=4m/s.Talk to our academic expert!
Similar Questions
The displacement of a particle moving in a straight line is described by the relation S=6+12t-2t2. Here s in meter and t is in sec. The distance covered by the particle in first 5s is
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