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A particle starts moving from rest from the origin with constant acceleration of 1  m/s2 and continues to move along X-axis. After sometime it starts moving with constant retardation of 2  m/s2 and finally stops at a point. If the total distance traversed by the particle is 12 m, its maximum velocity is

a
8 m/s
b
6 m/s
c
4 m/s
d
2 m/s

detailed solution

Correct option is C

(3)Vm2=0+2 × 1×x1  ⇒   x1=Vm22and   0=  Vm2−2  ×2 ×x2  ⇒   x2=Vm24Now,   x1 + x2 =12   ⇒    Vm22+Vm24=12   ⇒Vm=4m/s.

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