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Q.

A particle starts s with S.H.M. from the mean position . Its amplitude is A and its time periods T, At one time, its speed is half that of the maximum speed. What is thie distance of the particle from mean position at that instant ?

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a

2A3

b

3A2

c

2A3

d

3A2

answer is B.

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Detailed Solution

we know that v =ωA2−x21/2X=A2−V2ω21/2 Given that V=Aω2 so X=A2−A2ω24ω21/2=32⋅A
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