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A particle starts S.H.M. from the mean position. Its amplitude is a and total energy E. At one instant its kinetic energy is $3 E / 4$ . Its displacement at this instant is

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Correct option is B

Total energy, E=12 mω2a2K.E.=3E4=12 mω2(a2−y2) So, 34=a2−y2a2 ⇒ y2=a24 ⇒y=a2 .

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A particle starts S.H.M. from the mean position. Its amplitude is a and total energy E. At one instant its kinetic energy is 3E/4. Its displacement at this instant is

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A particle starts S.H.M. from the mean position. Its amplitude is a and total energy E. At one instant its kinetic energy is $3 E / 4$ . Its displacement at this instant is