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Simple harmonic motion
Question

A particle starts simple harmonic motion from the mean position. Its amplitude is a and total energy E. At one instant its kinetic energy is 3E/4.  Its displacement at that instant is

Moderate
Solution

KE=122(a2y2)122a2=a2y2a2=1y2a2

So, 3E4E=1y2a2y2a2=134=14 y=a2

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