Questions
A particle starts simple harmonic motion from the mean position. Its amplitude is a and total energy E. At one instant its kinetic energy is Its displacement at that instant is
a
a/2
b
a/2
c
a3/2
d
a/3
detailed solution
Correct option is B
KE=12mω2(a2−y2)12mω2a2=a2−y2a2=1−y2a2So, 3E4E=1−y2a2⇒y2a2=1−34=14 ⇒y=a2Talk to our academic expert!
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When the displacement is half the amplitude, the ratio of potential energy to the total energy is
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