The particle starts sliding down on smooth inclined plane.If Sn is distance travelled by a  body from t=n−1 sec to t=n sec then the ratio of SnSn+1 is

Distance travelled in t=n−1sec to t=nsec is  The acceleration =a ; initial velocity=UThe distance travelledin t=nSn=U+an−12⇒Sn=0+a(2n−1)2⇒Sn=a2(2n−1)---(1) The distance travelled in t=n+1sec is Sn+1=0+a(n+1)−12⇒Sn+1=a2(2n+1)---(2)divide eqn(2) by eqn(1)∴SnSn+1=a2(2n−1)a2(2n+1)SnSn+1=(2n−1)(2n+1)