Questions
The particle starts sliding down on smooth inclined plane.If is distance travelled by a body from to then the ratio of is
a
2n−12n+1
b
2n+12n−1
c
2n2n−1
d
2n2n+1
detailed solution
Correct option is A
Distance travelled in t=n−1sec to t=nsec is The acceleration =a ; initial velocity=UThe distance travelledin t=nSn=U+an−12⇒Sn=0+a(2n−1)2⇒Sn=a2(2n−1)---(1) The distance travelled in t=n+1sec is Sn+1=0+a(n+1)−12⇒Sn+1=a2(2n+1)---(2)divide eqn(2) by eqn(1)∴SnSn+1=a2(2n−1)a2(2n+1)SnSn+1=(2n−1)(2n+1)Talk to our academic expert!
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