A particle strikes a horizontal smooth floor with a velocity ‘u’ making an angle θ with the floor and rebounds with velocity ‘v’ making an angle ϕ with the floor. If the coefficient of restitution between the particle and the floor is ‘e’, then

Question

A particle  strikes a horizontal smooth floor with a velocity ‘u’ making an angle θ      with the floor and rebounds with velocity ‘v’ making  an angle ϕ      with the floor. If the coefficient of restitution  between the particle and the floor is ‘e’, then

Infinity Learn · Accepted Answer

vcosϕ$$=ucos$$θ  ……. (1)vsin$$ϕ$$=eusin$$θ  …….. $$(2)∴(1)2+(2)2$$→$$v=ucos2$$θ$$+e2sin2$$θ$$v=ucos2$$θ$$+sin2$$θ−$$sin2$$θ$$+e2sin2$$θ$$=u1$$−$$(1$$−$$e2)sin2$$θ$$(2)(1)⇒$$tan$$ϕ$$=etan$$θImpulse delivered by the floor to body $$=$$ mvsinϕ$$+musin$$θ$$=meusin$$θ$$+musin$$θ$$=mu(1+e)$$$$sin$$θ$$KEFKEI=12mv212mu2=cos2$$�$$+e2sin2$$�

A particle strikes a horizontal smooth floor with a velocity ‘u’ making an angle $θ$ with the floor and rebounds with velocity ‘v’ making an angle $ϕ$ with the floor. If the coefficient of restitution between the particle and the floor is ‘e’, then

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