Questions
A particle is subjected to a force F = -kx with k = 15 N/m. If it is released from a point 20 cm away from the origin, its kinetic energy when it is 10 cm from the origin is
detailed solution
Correct option is A
Potential energy U = ∫kxdx=12kx2loss in potential energy = Gain in kinetic energy. Its loss in potential energy from 0.2 m to 0.1 m12150.22-0.12=7.5×0.03=0.225 JTalk to our academic expert!
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In the figure given the position-time graph of a particle of mass 0.1 kg is shown. The impulse at t = 2 s is :
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