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Questions  

A particle  is subjected to a force F = -kx with k = 15 N/m. If it is released from a point 20 cm away from the origin, its kinetic energy when it is 10 cm from the origin is

a
0.225 J
b
0.45J
c
0.75J
d
0.075J

detailed solution

Correct option is A

Potential energy U = ∫kxdx=12kx2loss in potential energy = Gain in kinetic energy. Its  loss in potential energy from 0.2 m to 0.1 m12150.22-0.12=7.5×0.03=0.225 J

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