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Q.

A particle  is subjected to a force F = -kx with k = 15 N/m. If it is released from a point 20 cm away from the origin, its kinetic energy when it is 10 cm from the origin is

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a

0.225 J

b

0.45J

c

0.75J

d

0.075J

answer is A.

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Detailed Solution

Potential energy U = ∫kxdx=12kx2loss in potential energy = Gain in kinetic energy. Its  loss in potential energy from 0.2 m to 0.1 m12150.22-0.12=7.5×0.03=0.225 J
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