A particle is subjected to two SHM’s x1 = A1 Sinωt and x2 = A2 Sin(ωt + π/4). The resultant SHM will have an amplitude of

∅=π4 The resultant SHM will have an amplitude=A=A12+A22+2A1A2cos∅ given phase difference ∅=π4      =A12+A22+2A1A2cosπ4       =A12+A22+2A1A212       resultant amplitude=A12+A22+2A1A2