First slide
Simple hormonic motion
Question

A particle is subjected to two SHMs, X1=A1 sin ωt and X2=A2 sin ωt+π4. The resultant SHM will have an amplitude of:

Moderate
Solution

Resultant amplitude, 
AA12+A22+2A1A2cos ϕ
Here        ϕ=π4
     A=A12+A22+2A1A2
 

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