A particle is subjected to two SHMs, X1=A1 sin ωt and X2=A2 sin ωt+π4. The resultant SHM will have an amplitude of:
A1+A22
A12+A22
A12+A22+2A1A2
A12+A222
Resultant amplitude, AA12+A22+2A1A2cos ϕHere ϕ=π4⇒ A=A12+A22+2A1A2