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Questions  

A particle is subjected to two SHMs x1=A1sinωt and x2=A2sinωt+π4. The resultant SHM will have an amplitude of

a
A1+A22
b
A12+A22
c
A12+A22+2A1A2
d
A1A2

detailed solution

Correct option is C

A=A12+A22+2A1A2cosϕ

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