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Q.

A particle is taken from point A to point B under the influence of a force field. Now it is taken back from B to A and it is observed that the work done in taking the particle from A to B is not equal to the work done in taking it from B to A. If Wnc, and Wc are the work done by non-conservative and conservative forces present in the system, respectively, ΔU is the change in potential energy and Δk is the change in kinetic energy, then

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a

Wnc−ΔU=Δk

b

Wc=−ΔU

c

Wnc+Wc=Δk

d

Wnc−ΔU=−Δk

answer is A.

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Detailed Solution

According to the work-energy theorem for a non-conservative system, we have Wc+Wnc=ΔKAlso, we know that the work done by a conservative force equals the decrease in potential energy, so Wc=−ΔUWnc−ΔU=ΔK
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A particle is taken from point A to point B under the influence of a force field. Now it is taken back from B to A and it is observed that the work done in taking the particle from A to B is not equal to the work done in taking it from B to A. If Wnc, and Wc are the work done by non-conservative and conservative forces present in the system, respectively, ΔU is the change in potential energy and Δk is the change in kinetic energy, then