A particle is taken from point A to point B under the influence of a force field. Now it is taken back from B to A and it is observed that the work done in taking the particle from A to B is not equal to the work done in taking it from B to A. If Wnc, and Wc are the work done by non-conservative and conservative forces present in the system, respectively, ΔU is the change in potential energy and Δk is the change in kinetic energy, then
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a
Wnc−ΔU=Δk
b
Wc=−ΔU
c
Wnc+Wc=Δk
d
Wnc−ΔU=−Δk
answer is A.
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Detailed Solution
According to the work-energy theorem for a non-conservative system, we have Wc+Wnc=ΔKAlso, we know that the work done by a conservative force equals the decrease in potential energy, so Wc=−ΔUWnc−ΔU=ΔK